New kind of catalysts. An example. - Apr. 22, 2026.
New kind of catalysts. An example - Apr. 22, 2026. David Judbarovski, systems engineering, principle inventor, judbarovski.blogspot.com, judbarovski@gmail.com. (1) 0.5 Al + 1.5 H2O = 0.5 Al2O3 + 1.5 H2 dH = - 470 kJ/mol, spontaneous reaction. (2) 0.5 Al2O3 + 2 NH3 = 0.5 Al + 1.5 H2O + 1.5 H2 + N2. dH = 566, dS = 380, and T > 1220 C, They are circular chemistry, and totaly (1) + (2) is 2 NH3 = N2 + 3 H2, and can be considered as a catalyst (in wide sence) for the water thermachemical splitting. 1 mol of cathalist for M moles of the water. dG = (M * 242 - 470) - T * (M * 54 + 579) (M * 242 - 470) / (M * 54 + 579). If M = 4, T > 350 C, and because (1) + (2) are circular and practically free, so OPEX cost of hydrogen product of the said chemistry is a cost of energy consumed. So the said hydrogen cost (OPEX) is 566 kJ from reaction 2 - 479 kJ from reaction 1 and - 92 kJ(NH3), so hydrogn is free too or so. References. 2021 Annual Meeting. (397e) Cheap Energy is a Key to Competitive...