Reflector for PV-module - corrected

Reflector for PV-module. Evaluation Author: David Judbarovski, engineering systems, principle inventor judbarovski@gmail.com , Linkedin Abstract Being in order of magnitude cheaper than PV-panels, a reflector serves to add additional sun on PV-module. Depended on a latitude and climate, the said system can harvest in order of magnitude more sun than motionless conventional PV-module and more powerful and more simple and reliable designed than other tracking PV-receivers. For Israel/Jordan area, a cost of electricity could be cheaper USD 0.1 /kWh Disclosure for experts If A – angle of sun above horizon B – angle of reflector above horizon Lr (m) – length the reflector, and Br (m) = Bpv (m) – width of it, and Sr (sq. m) – its area Spv (sq. m) – area of PV-module, 1 m2 Lpv (m) – its length, 1 m Bpv (m) – its width. 1 m [Wpv] (kW) – solar power harvested by the said PV-module of 1 m2 = 1 m * 1 m B = 45 + A/2 Such B redirects solar flux vertically on PV-panel or on a part of it. [Wpv] kW= Kdir * (Sr * Cos B + sin A) + Kdiff, if Spv > Sr * Cos B or [Wpv] kW = Wdir * (1 + sin A) + Kdiff, if Spv < Sr * Cos B (Here [Wpv], Kdir, and Kdiff are power of PV-module, a share of Normal Direct Radiation in total radiation , and a share Diffuse Radiation in total radiation correspondingly. Really, At the angle C of solar flux to the reflector, C = B - A = 90 – B, So 2 * B = 90 + A, and B = 45 + A/2. Q.E.D. ! If Wsr (kW/sq.m) –direct solar radiation onto the reflector Wdir (kW/sq.m) – Direct Normal Radiation (DNR). Wpv – power reflected onto PV-module of 1 m2 = 1 m * 1 m Sdir (sq.m) – cross-section of the DNR, illuminating the reflector Spv (sq.m) = 1.0 m * 1.0 m – PV-module area totally or partly illuminated by Wsr Sr (sq.m) – area of reflector. So Wsr * Sr = Wdir * Sdir Wsr = Wdir * Sdir / Sr = Wdir * sin C = Wdir * cos B Wpv = Wdir * (Sr * cos B) if Spv > Sr * Cos B. And Wpv = Wdir , if Spv < Sr * Cos B