Advanced fuel and its recycling. Half-green variant. Edited.

 


Advanced fuel and its recycling. Half-green variant. Edited. Author: David Judbarovski, systems engineering, principle inventor, retired. Linkedin. judbarovski.blogspot.com. Abstract. MgH2 + 2 H2O = Mg(OH)2 + 2 H2- 278 kJ; 278 * 0.03 (energy efficiency) = 90 kJ electricity; 2 H2 = PEM electrolysis = 640 kJ, and totally 90 + 640 = 730 kJ electricity = 7900  kwh/MT MgH2. Recycling. Mg(OH)2 = MgO + H2O -38 kJ; MgO + CO = Mg + CO2 ( used in cycle) -318 kJ. 0.5 C + 0.5 CO2 = CO -86 kJ; Mg + H2 = MgH2 +75 kJ; CO + H2O = H2 + CO2 -3 kJ, and totally 370 kJ = 3950 kwh/MT MgH2 + 0.5 mol coal consume and 1.5 mol CO2 exhaust per mol MgH2. It allows to solve now unsolvable problem of integration huge renewable energy in national grids for energy production of any designed schedule, practically without loses during delivery and for war time and against terrorists attack. For example. for gigantic USA economics, it can be introduced without any problems to integrate it in national grid, decreasing CO2 emission in the air in two order of magnitude and consuming 0.12% of GDP for fueling. For Japan it is 0.1%. for Germany it is 0.25 %.

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