The water thermolysis by CO2 + H2 circular

(1) CO + H2O (gas) = CO2 + H2, dH = - 41 kJ/mol. dS = - 86 J/mol *K, and T < 200 C. (2) CO2 + H2 + k*(H2O = H2 + 0.5 O2) + CO + H2O, T > (41 + k*242) / (86 + k*54), and at k = 0.25, T>750C. So H2 (OPEX) = (41 + 0.25 * 242) * 1.1 / 0.5 - (41 * 10^6 /3600) * 0.15 * 0.03 = USD 120 /ton H2. if treated H2O being liquid and k = 0.25, dG = (- 3 + k * 286) * 1000 - (86 + k * 160) < 0, T > 270 C.

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