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Energy and water production by artificial condensation of vapor above LCL

Author: David Judbarovski, systems engineering, Israel, retired engineer

judbarovski@gmail.com , Linkedin: David Judbarovski

13.08.2017

Energy and water production by artificial condensation of vapor above LCL
Author: David Judbarovski, systems engineering, Israel, retired engineer
judbarovski@gmail.com , Linkedin: David Judbarovski
11.08.2017
Humidity being above the LCL (lifted condensation level), is looked much more concentrated and cheap resource, than water droplets harvesting by meshes.
I consider a horizontal thin film to be placed above the LCL, and it is enough for the dew fall on the film surface at both sides of it, and some big layers of the films, are one above others with a gap between them allows practically all air humidity to be harvested by all height and width of the said construction. The layers are sloped to their central axis, and the water condensate are flowing to the ground level and moves an electric generator to produce a electricity. Such water and electricity would be much cheaper, than conventional tariffs for them.   
Hydrogen balloon lifts and stabilizes the said construction at operating altitude and control it. The said thin films are reinforced by nets.  
Numerical evaluation
V (m/s) – horizontal wind velocity
C (g/m3) – extractable air humidity
T (Centigrade) – ambient vapor at water production
dT = the dew overheating  ~= the air overheating during the dew fall
K – share of the C extraction
H (m) – gap
B (m) – a layer width
L = B (m) – a layer length
q (USD/m2) – construction cost of a layer
a – factor of convective heat transfer

For C = 3.0; T = +5 (2.5 km altitude), dT = 1.5
dT ~= 2.4 kJ/g * 3 *.K / 0.9 kg/m3 ~= 1.5, so K = 0.19
Condensation heat would be 
V * H * B * C * K * 2400 (J/g) must be fully dispersed by convections, so
2 * a * (T – 1.5) * B^2 * = 2400 * V * H * B * C * K (Watt), or
supposing V ~= 10 m/s, and a ~= 300 at the V, C ~= 3.0 g/m3, and T ~= 5 Centigrade, so
600 * B * 3.5 = 13600 * H, so
B = 6.5 * H   and supposing H = 6.0 m,
B ~= 40 m, and
the water production would be V * H * B * C * K= 1.36 kg/s ~= 40,000 ton/year per one layer. Or about 40,000 ton * 5 years of payback = 125 ton/m2 = 0,008 USD/m3 of water.
Supposing 10 layers, we can produce 400,000 ton water per a year by equipment of 40 m * 40 m and 60 m height. Its cost of being 0.8 USA cent/m3 H2O plus about 40 kW electricity free for about 100 householders  


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