Take-off and Landing Device - 20.07.2020

Take-off and landing device 

Author: David Judbarovski, sysiems engineering, principle inventor, retired

judbarovski@gmail.com

The four movers are placed at the ends of a cross, fixed to a vehicle.

It is a take-off and landing device 

Each mover is a container with a water pump. Its inlet pipe is short and wide, and its exhaust pipe is short and thin and used as a nozzle creating a lift force, while the water fall is collected in small amount on the bottom and used as the pump intake.

The water collecting and used in the cycle, it halves the lift force created by energy consumed by the pump. Total 40 kW, 8.0 atm. pumps per a ton, can keep the weight at designed altitude

It can be quickly modeled and simply scaled

Really,

Q = F / v ; v^2 = 2 * g * 10 * P; S = Q/ v/ 1000 (m2) = 10 * Q/ v (cm2); F1 = 10 * p * S

Q (kg/s) – jet exhaust

F (Newton) – lift force

v (m/s) – water stream through the jet’s nozzle.

P (atm) – the pump pressure

g = 9.8 m/s2  

S (cm2) – nozzle

F1 (Newton) – loss of the lift force

F1 = F / 2 – it can be obtained after correct calculations 

Really,

F1 = 10 * S * P = 10 * (10 * Q/ v) * (v^2 / (2 * g * 10)) =  10 * Q * v / ( 2 * g) =

~= Q * v / 2 = F / 2  

To keep 1 ton = F – F1 = F/ 2, F = 2 ton = 20,000 N is needed.

If P = 8 atm, so v^2 = 2 * g * 10 * P = 1600, so v = 40 m/s and

Q = F/v  = 20,000 / 40 = 500 kg/s

So the pump power is W = Q * 10 * P = 500 * 10 * 8 (watt) = 40 kW/ton